WebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5 Sum of n terms of AP, Sn = (n/2) [2a+ (n-1)d] Let there be n terms in the AP such that Sn= 148 148= (n/2) [2 (1)+ (n-1) (5)] 148 = (n/2) [2+5n-5] 148 = (n/2) [5n-3] 5n²-3n-296=0 This equation has one +ve root, n= 8 8 terms of AP are , 1, 6, 11, 16, 21, 26, 31, 36 Ans: 8 terms 1 Web28 mrt. 2024 · Class 11 Class 11 Maths; Class 11 Computer Science (Python) ... Chapter 5 Class 10 Arithmetic Progressions (Term 2) Last updated at March 28, 2024 by Teachoo. This video is only ... Get live Maths 1-on-1 Classs - Class 6 to 12. Book 30 minute class for ₹ 499 ₹ 299. Transcript. Show More. Next: Ex 5.3, 5 → Ask a doubt . Chapter ...
HOW MANY TERMS OF THE AP. -6, -11/2, -5... are needed to …
WebThe AP is -6, -11/2, -5, … It is an AP with the first term as -6 and the common ratio is 1/2. Sn = -25 = (n/2) [2a + (n-1)d] = (n/2) [-12 + (n-1)* (1/2)] = (n/2) [-12–1/2 + (n/2)] = (n/2) [-25/2 + (n/2)] -25*4 = n [-25+n] n^2–25n+100 = 0 (n-20) (n-5) = 0 n = 20 or 5. So either 5 terms or 20 terms of the AP will add up to -25. Answer. 2.1K views WebFirst term of the AP = 65 Common difference = 60 − 65 = −5 Let the sum of the first x terms of the AP be 0. Sum of first x terms = x 2 [2×65+(x−1)(−5)]=0 ⇒ x 2 [130+(−5x+5)]=0 ⇒x(130−5x+5)=0 ⇒x(135−5x)=0 Now, either x = 0 or 135 − 5x = 0. Since the number of terms cannot be 0, x≠0. ∴ 135 − 5 x = 0 ⇒ 135 = 5 x ⇒ x = 27 florence livestock
How many terms of the A.P. – 6, –11/2 , – 5, - Sarthaks
WebAP will be –15, –13, –11, –9, –7 So, resulting sum will be –55 because all terms are negative. When n = 11, AP will be –15, –13, –11, –9, –7, –5, –3, –1, 1, 3, 5 So resulting sum will be –55 because the sum of terms 6 th to 11 th is zero. Concept: Sum of First n Terms of an A.P. Is there an error in this question or solution? WebFind an answer to your question c) How many terms of the AP 7, 11, ... Advertisement Advertisement Sankalp050 Sankalp050 QUESTION: How many terms of an arithmetic sequence 7,11,15,… must be added to get sum 250? Solution: 7, 11, 15, 19, 23 . . . . . . In the above AP, first term ‘a’= 7. WebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5. Sum of n terms of AP, Sn = (n/2)[2a+(n-1)d] Let there be n terms in the AP such that Sn= 148. 148= … great sphinx tail