Web>> Sum of an AP >> How many terms of the series 54, 51, 48, Question . 48 be taken so that their Tupe ION RIDING THE NUMBER OF TERMS IRAILA EXAMPLE 11 How many terms of the series 54. 51, 48.... be taken so that their El the downs. n d the given sequence is an A.P. with first term a. Open in App. Solution. WebVerified Answer How to many terms of the series 54, 51,48 . be taken so that their sum... Use forumla , Sn=n/2 {2a+ (n-1)d} from series , a=54 d=-3 Sn=513 now, 513=n/2 {54 x 2+ (n-1) (-3)} 1026=n {108+3-3n} =111n-3n^2 3n^2-111n+1026=0 n^2-37n+342=0 use quadratic formula , n= {37+_√ (1369-1368)}/2 = (37+_1)/2=19 and 18

Arithmetic Progressions - Aptitude - UPSCFEVER

WebHow many terms of the series 54, 51, 48, …. be taken so that their sum is 513 ? Explain the double answer Advertisement Remove all ads Solution ∵ a = 54, d = – 3 and S_n = 513 … WebCorresponding terms of A.P = first and last, second and second last etc. So if an AP is 1,2,3,4,5,6 then corresponding terms are (1,6) , (2,5) , (3,4). Average of the A.P = mean of the corresponding terms e.g: 1+6/2 or 2+5/2 etc Sum of A.P = ( Average of A.P. ) * ( Number of terms ) north end property management

Test: Sum of n Terms of AP - EDUREV.IN

Web16 nov. 2016 · FIND THE NUMBER OF TERMS OF THE A.P 54,51,48.........SO THAT THEIR SUM IS 513 See answers Advertisement Golda Solution:- Given : a = 54, d = - 3 … Webtotally 18 terms are required to make sum as 513. 54 +51+ 48 +45 +42 + 39+ 36 +33 +30 +27 + 24 +21 +18 + 15 + 12 + 9 + 6 +3 = 513 WebAnswer (1 of 5): In the above AP series it is given that Sn = 513 a = 54 d = (-3) n = ? We know Sn = n/2(2a+(n-1) d) Therefore 513 =n/2(2×54) +(n-1) (-3) 1026 = n(108-3n+3) =108n-3n^2+3n 3n^2-108n-3n+1026 = 0 Dividing above equation by 3 n^2-36n-n+342 = 0 n^2-37n+342 = 0 n^2–18n-19n... northend print sheffield